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  VS Arduino › Visual Micro › Visual Studio 2017, 2019, 2022 › if #ifdef _DEBUG working?
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Normal Topic if #ifdef _DEBUG working? (Read 7436 times)
Massimo S
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if #ifdef _DEBUG working?
Sep 3rd, 2015 at 7:27pm
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On VisualStudio I added a log library and all log statement should be under #ifdef but it appears they are ignored.
Is it working? am I doing something wrong?
  
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Tim@Visual Micro
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Re: if #ifdef _DEBUG working?
Reply #1 - Sep 3rd, 2015 at 9:03pm
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Hi,

If you search visualmicro.com or the forum for _debug you should get a few hits.

The VS project properties are not used. You can achiever the same thing using the _debug constant available in the VM project properties.

http://www.visualmicro.com/search.aspx?q=_debug

  
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Massimo S
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Re: if #ifdef _DEBUG working?
Reply #2 - Sep 3rd, 2015 at 9:43pm
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ops! sorry for my dummyness and thank you!
  
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Tim@Visual Micro
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Re: if #ifdef _DEBUG working?
Reply #3 - Sep 3rd, 2015 at 9:49pm
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No problem. Hopefully an "advanced"option is coming soon that will allow more control using standard vs project and solution config.
« Last Edit: Sep 3rd, 2015 at 9:49pm by Tim@Visual Micro »  
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Massimo S
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Re: if #ifdef _DEBUG working?
Reply #4 - Sep 3rd, 2015 at 10:30pm
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This is great Smiley

But I'm confused...
I've read a lot of pages and I did the project properties Define _DEBUG constant 1
Then I changed the code in:
#if !defined(VM_DEBUG)

as written in docs but when I change from Debug to Release the code does not gray out and the memory footprint is the same.

What am I doing wrong?
  
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Tim@Visual Micro
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Re: if #ifdef _DEBUG working?
Reply #5 - Sep 3rd, 2015 at 10:35pm
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The _DEBUG constant is per configuration. It's shown in the wrong section of the properties so this is not clear.

eg: You can have one settings for Release and one for Debug.
« Last Edit: Sep 3rd, 2015 at 10:35pm by Tim@Visual Micro »  
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