VS Arduino - Can't use user-defined data types as arguments to functions???

Jul 9^th, 2025 at 7:53pm (UTC)

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VS Arduino › Visual Micro › Installation & Troubleshooting › Can't use user-defined data types as arguments to functions???

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Can't use user-defined data types as arguments to functions??? (Read 2480 times)

Randy P. Newbies Offline Posts: 2 Joined: Jul 10^th, 2016	Can't use user-defined data types as arguments to functions??? Jul 10^th, 2016 at 4:41pm	Print Post
	The statement "You cannot use user defined data types like your own classes, structs or typedefs as arguments to functions." in an ".ino" file is made on this Visual Micro page: http://www.visualmicro.com/page/User-Guide.aspx?doc=INOs-and-CPPs.html But I'm confused. Why can't I pass a user-defined structure to a function??? Thanks. Randy


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Tim@Visual Micro Administrator Offline Posts: 12191 Location: United Kingdom Joined: Apr 10^th, 2010	Re: Can't use user-defined data types as arguments to functions??? Reply #1 - Jul 10^th, 2016 at 6:38pm	Print Post
	Hi, Thanks for the post. We are going to change the docs. You can use them but you need to create the prototype(s) yourself instead of relying on the automatic system. Code (C++) //1. Define types struct mytype {} //2. Create prototype with the exact same signature as the corresponding method void test(mytype a); //3. Method that uses the type void test(mytype a) { } Note about auto-generated prototypes More recently the Arduino IDe has been updated to insert auto generated prototypes at the correct code location. Over the next month or so Visual Micro will be changed to work the same way but in the meantime you can control the insertion point by adding them yourself.
	« Last Edit: Jul 10^th, 2016 at 6:39pm by Tim@Visual Micro »

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Randy P. Newbies Offline Posts: 2 Joined: Jul 10^th, 2016	Re: Can't use user-defined data types as arguments to functions??? Reply #2 - Jul 10^th, 2016 at 8:57pm	Print Post
	Okay, that's a relief! Thanks for spelling it out for me, and for updating the docs and soon the code Randy


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