VS Arduino - VS Build Configurations

May 7^th, 2025 at 11:25pm (UTC)

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VS Build Configurations (Read 2475 times)

RayLivingston Full Member Offline Posts: 158 Location: California Joined: Nov 24^th, 2012	VS Build Configurations Jan 28^th, 2017 at 8:13pm	Print Post
	I can't for the life of me figure out how to put a conditional in the code that is dependant on whether I can doing a Debug or Release build. My understanding is VS should include a _DEBUG #define for a Debug build, but I am not seeing it. What am I missing? Regards, Ray L.


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Tim@Visual Micro Administrator Offline Posts: 12187 Location: United Kingdom Joined: Apr 10^th, 2010	Re: VS Build Configurations Reply #1 - Jan 28^th, 2017 at 8:34pm	Print Post
	Hi, Vs and arduino have different systems so you should use the visual micro project property called "define _DEBUG constant. The property is fed to VS for intellisense and arduino for compile. In the current release the property is in the wrong section (see attached picture). The property is a Configuration specific property and should be in the section above. You can use the property to assign a number, if 0 the #define is excluded. Click "vMicro>Project Properties" or right click project name > properties
	« Last Edit: Jan 28^th, 2017 at 8:36pm by Tim@Visual Micro »
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RayLivingston Full Member Offline Posts: 158 Location: California Joined: Nov 24^th, 2012	Re: VS Build Configurations Reply #2 - Jan 28^th, 2017 at 8:56pm	Print Post
	Tim, That works! Thanks! Regards, Ray L.


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